How to calculate the size of stirrups of a face extended beam??????

How to calculate the size of stirrups of a slope with face extended beam?????

There are so many beams execute at working site, Slope with face extended beam is one of them. We are going to calculate stirrup sizes of slope with face extended beam. let's calculate the stirrup sizes of face extended beam by interpolation formula.
Formula-
Y=Y 1+((Y 2 - Y 1)/(X 2 - X 1))*(X 0- X 1 )

                                                                                            Diagram-


                                                              
                                                                                                 


In interpolation  we take the ratio of  (RISE/RUN). In diagram x- indicates (RUN) & y- indicates (RISE)

 Problem-
A 1.2 m slope beam having 600 mm depth in one end & 1500 mm depth in another end, width of beam is 300 mm. 8 mm dia stirrups having 200 mm c/c. Prepare BBS of  this beam.

 Solution-

 Nos of stirrups = ( 1200 mm/200 mm ) + 1 = 7 nos.

 1.  Size first ring = ( width- 2* cover ), ( Depth- 2 * cover )
  = ( 300 - 2 * 25 ), ( 600 - 2 * 25 )
  = ( 250 * 550 ) mm

( Width for beam remain constant for all stirrups)

 2. (Second - Seventh) ring depth is increase due to slope, let's calculate i.e.,






        
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